![]() High Demand / High Value = Multiple builds use these items, they can be worth High Runes, or they are instantly tradeable (Griffon’s Eye, Hellfire Torch).Let’s quickly go over the categories of items in D2R: More importantly, I’m going through every unique and set item in the game so you can search this list and judge if that item you just found is worth stashing or if it’s safe to trash it. The answer is not always simple, but I hope after reading this guide you will have a better grasp of these values. This guide focuses on unique and set items and answers that question we’ve all had: Is this worth keeping? ![]() The dictionary has around 400,000 words I will be adding.Welcome to a guide about what Diablo 2 Resurrected items to keep. My data structures class never went over hash tables and maps so this is my first attempt. If (!currentWordStack.empty()&letters = currentWordStack.top())Ĭout << currentWord << "\n \n \n \n \n \n \n " }//AFTER THIS LINE THE currentWordStack SHOULD HAVE THE WHOLE WORD.įor (unsigned int z = 0 z < letters.size() z++)//THIS LOOP WILL EMPTY THE STACK IF THE LETTERS CAN MAKE UP THAT WORD ![]() Here is the current implementation using a Vector string currentWord įor (unsigned int i = 0 i < dictionary.size() i++)//OUTERMOST LOOP CYCLES THROUGH ALL WORDS IN DICTĬurrentWord = dictionary //TEMPORARILY STORES THE CURRENT WORD IN A STRING"currentWord"įor (unsigned int x = 0 x < currentWord.size() x++) My problem is I don't understand how I can search through the map effeciently. I am working on implementing a Wordament solver and I'm considering using an unordered_map as the data structure to hold my Dictionary.
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